A microwave detector is moved steadily in a straight line from X to Y. A series of maxima and
minima of intensity is obtained. The distance between adjacent maxima is 1.5 cm.What is the frequency of the microwave radiation?
A 1.0 × 108Hz
B 2.0 × 108Hz
C 1.0 × 1010Hz
D 2.0 × 1010Hz
Solution:
Answer: C
distance between adjacent maxima = λ /2
f = v/λ
f = (3.0 x 108 ms-1) / (2 x 1.5 x 10-2 m)
= 1.0 x 1010
Hz
*To answer this question successfully, candidates needed to realise that the distance between intensity maxima in a stationary wave pattern is half the wavelength of the wave. Many candidates chose D because they thought that the measured distance was equal to the wavelength.
Reference: PYQ - Oct/Nov 2016 Paper 12 Q29
thank you :)
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