waves from X have the same amplitude as the waves from Y. Distances XZ and YZ are as
shown.
When the wave generators operate in phase, the amplitude of oscillation at Z is zero.
What could be the wavelength of the waves?
A 2 cm
B 3 cm
C 4 cm
D 6 cm
Solution:
Answer: C.
The amplitude of oscillation at Z is zero, so destructive interference occurs at Z and the difference between lengths XZ and YZ must be an odd number of half-wavelengths.
Path difference between XY and YZ = 34 – 24 = 10cm
This path difference must be an odd number of half-wavelengths.
(n + ½) λ = 10cm
Wavelength λ = 10 / (n + 0.5)
Put n = 0, Wavelength λ = 10 / (0 + 0.5) = 20cm
Put n = 1, Wavelength λ = 10 / (1 + 0.5) = 6.67cm
Put n = 2, Wavelength λ = 10 / (2 + 0.5) = 4cm [C is correct]
Put n = 3, Wavelength λ = 10 / (3 + 0.5) = 2.86cm
…
Reference: PYQ - May/Jun 2015 Paper 13 Q29
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