acceleration a. The person needs to push the car with force 2F in order to give the car
acceleration 3a.
Which expression gives the constant resistive force opposing the motion of the car?
A ma
B 2ma
C 3ma
D 4ma
Solution:
Answer: A
Resultant force = applied force – resistive force
Ma = F- R
R = F- ma —-i
3ma = 2F – R
R = 2F – 3ma —–ii
Substitute for R in eq i
2F – 3ma = F – ma
F = 2ma
Therefore, R = 2ma – ma = ma
Resistive force = ma (A is the correct option)
Reference: PYQ - Oct/Nov 2016 Paper 11 Q11
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